Answer: 1560
Step-by-step explanation: The average rate of change of a function over an interval is the total change in the value of the function divided by the length of the interval. In this case, the function is f(x) = 10(2)^x and the interval is [3, 5].
To find the average rate of change of the function over the interval, we can first evaluate the function at the two endpoints of the interval, which are x = 3 and x = 5. At x = 3, the function has a value of f(3) = 10(2)^3 = 80. At x = 5, the function has a value of f(5) = 10(2)^5 = 3200.
The total change in the value of the function over the interval is then the difference between the values at the two endpoints, which is f(5) - f(3) = 3200 - 80 = 3120.
The length of the interval is 5 - 3 = 2, since it goes from x = 3 to x = 5. Therefore, the average rate of change of the function over the interval is the total change in the value of the function divided by the length of the interval, which is (3120) / 2 = 1560.
Therefore, the average rate of change of the function f(x) = 10(2)^x on the interval [3, 5] is 1560.