Final answer:
The concentration of the KOH solution reacting with H2SO4 is found using stoichiometry of the balanced chemical reaction.
Step-by-step explanation:
The student is asking how to determine the concentration of a KOH solution when reacted with a given amount of H&sub2;SO&sub4;. We can use the stoichiometry of the balanced neutralization reaction, which tells us that it takes two moles of KOH to neutralize one mole of H&sub2;SO&sub4;. This reaction is represented as:
H&sub2;SO&sub4; + 2KOH → 2H&sub2;O + K&sub2;SO&sub4;
First, we calculate the moles of H&sub2;SO&sub4;:
Moles H&sub2;SO&sub4; = 0.909 L × 0.210 M = 0.19089 moles
Using the stoichiometry from the balanced equation, we need twice as many moles of KOH to react completely with H&sub2;SO&sub4;, so we need:
Moles KOH required = 2 × moles H&sub2;SO&sub4; = 2 × 0.19089 mol = 0.38178 moles
The volume of KOH has been given as 0.427 L. The concentration of KOH can be found using the formula:
Concentration KOH = moles KOH / volume KOH = 0.38178 mol / 0.427 L = 0.89345 M
Therefore, the concentration of KOH is 0.893 M.
By calculating the moles of H2SO4 and applying the stoichiometric ratio, we determine that the concentration of KOH is 0.893 M.