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Sheila, Melanie, and Claudette live in different towns, as shown on the map. Whenever they visit Melanie, Sheila and claudette leave their houses at the exactly same time . Claudette always travels at 75 km/hr. If sheila travels at 105 km/h , use an inequality to determine after what amount of time she is closer to Melanie's house than Claudette.

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Final answer:

There is no amount of time after which Sheila is closer to Melanie's house than Claudette.

Step-by-step explanation:

To determine after what amount of time Sheila is closer to Melanie's house than Claudette, we can set up an inequality based on the distances traveled by both Sheila and Claudette.

Let t be the time in hours that has passed since they left their houses.

Distance traveled by Claudette = 75t

Distance traveled by Sheila = 105t

To find when Sheila is closer to Melanie's house than Claudette, we need to find the time at which the distance traveled by Sheila is less than the distance traveled by Claudette. So we need to solve the inequality 105t < 75t.

Simplifying the inequality, we get 30t < 0. Dividing both sides by 30, we get t < 0. Since time cannot be negative, there is no solution to this inequality.

Therefore, there is no amount of time after which Sheila is closer to Melanie's house than Claudette.

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