Question

Question 2 (5 points) (04.01 LC) Simplify +5x+6 X+2

A x²+1
B x²-1
C X +3
D X-3​

Answer 1

`\bf{(x^(2) +5x+6 )/(x+2) }`

Rewrite the term.

x² + 2x + 3x + 6

Group the terms into two fractional parts.

(x² + 2x + (3x + 6)

Factor the expression

x(x + 2) + 3 (x + 2)

`\boldsymbol{\sf{\frac{(\\ot{x+2)(x+3)}}{\\ot{x+2}}=x+3 \to Option \ C }}`

Answer 2

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{\cfrac{x {}^(2) + 5 x + 6 }{x + 2} }`

Answer :

Note: To solve a problem like this, we must first determine which of the two numbers add 5 and multiply 6, we know that they are 2 and 3 and then we must Rewrite the expression using the above.

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{(x+2)(x+3)}`

Now, we must put a fraction since we can more easily solve the problem posed.

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{ \cfrac{(x + 2)(x + 3)}{x + 2} }`

Now the last thing we have to do is Cancel
`\bold{x+2}` to have a final result that is the following:

`\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{x+3}`