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(3) Compare the cost of using a television for 50 hours a month (30 days) during peak hours to using it during off-peak hours. Assume the television uses 0.5 kW of energy. [ 14A] Peak hours rate: 10cents/KW*h Off Peak rate: 6cents/KW*h

User Alyson
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Final answer:

To calculate the cost of using a television for 50 hours a month, multiply the power usage (0.5 kW) by the time (50 hours) and the rate (10 cents per kWh for peak hours, 6 cents per kWh for off-peak hours). The cost for peak hours is $2.50, whereas for off-peak hours, it is $1.50, resulting in savings of $1.00 during off-peak hours.

Step-by-step explanation:

To compare the cost of using a television during peak hours and off-peak hours, we use the following formula for the cost of electricity:

Cost = Power (kW) × Time (h) × Rate (cents/kWh)

Given that the television uses 0.5 kW of energy, for peak hours the calculation would be:

Cost (Peak Hours) = 0.5 kW × 50 h × $0.10/kWh

= $2.50

For off-peak hours, the calculation is:

Cost (Off-Peak Hours) = 0.5 kW × 50 h × $0.06/kWh

= $1.50

Therefore, using a television for 50 hours a month during off-peak hours saves $1.00 compared to using it during peak hours.

User El Che
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