To frame the entire perimeter of an 18-foot long-jump pit with pieces of wood measuring 6 feet each, approximately 10 pieces of wood would be needed (18+18+6+6 = 48 feet perimeter).
To find the number of pieces of wood needed to frame the entire perimeter of the rectangular long-jump pit with a length of 18 feet, we can calculate the perimeter using the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
Given that the length of the long-jump pit is 18 feet, let's assume the width is also known or set at a specific value. The total length of the perimeter is then twice the sum of the length and width.
Assuming a width of w feet, the perimeter is P = 2(18 + w) feet. Now, each piece of wood measures 6 feet, so the number of pieces needed can be calculated by dividing the perimeter by the length of each piece: number of pieces = P / 6.
For instance, if the width is 10 feet, the perimeter would be 2(18 + 10) = 56 feet. The number of pieces required would then be 56 / 6 ≈ 9.33. Since the number of pieces must be a whole number, you would need to round up to 10 pieces.
In conclusion, the number of pieces of wood needed depends on the dimensions of the long-jump pit, with the given information allowing for a specific calculation based on the length and width of the pit.
the probable question maybe:
If the long-jump pit is rectangular and has a length of 18 feet, how many pieces of wood, each measuring 6 feet, would be needed to frame the entire perimeter of the long-jump pit?