Final answer:
The impulse on the arrow, which is the product of its mass and change in velocity, is 2.37 kg·m/s.
Step-by-step explanation:
To find the impulse on the arrow, you need to use the impulse-momentum theorem. Impulse is defined as the change in momentum of an object when a force is applied over a period of time. The formula for impulse (I) is I = Δp = m ∙ Δv, where Δp is the change in momentum, m is the mass of the object, and Δv is the change in velocity.
In this case, since the arrow starts from rest, the initial velocity (vi) is 0 m/s, and the final velocity (vf) is 87.3 m/s. The mass of the arrow is 0.0272 kg. Thus, the impulse on the arrow is:
I = m ∙ Δv
I = 0.0272 kg ∙ (87.3 m/s - 0 m/s)
I = 0.0272 kg ∙ 87.3 m/s
I = 2.37456 kg∙m/s
Therefore, the impulse on the arrow is 2.37456 kg∙m/s (rounded to 2.37 kg∙m/s when considering significant figures).