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A bungee jumper falls off a tower and travels 2 seconds before the bungee cord starts to slow her down. What was her average velocity in free fall?

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Final answer:

The average velocity of the bungee jumper in free fall is -9.8 m/s.

Step-by-step explanation:

The average velocity of the bungee jumper in free fall can be calculated using the formula:

average velocity (v) = displacement (Δx) / time (Δt)

Since the bungee jumper falls for 2 seconds before the bungee cord starts to slow her down, and the positive direction is downward, the displacement (Δx) can be calculated as:

displacement (Δx) = initial velocity (vi) * time (Δt) + 0.5 * acceleration (a) * time (Δt)^2

Given that the initial velocity (vi) is 0 m/s and the acceleration (a) due to gravity is -9.8 m/s², the displacement (Δx) can be calculated:

displacement (Δx) = 0 * 2 + 0.5 * -9.8 * 2^2 = -19.6 m

Therefore, the average velocity in free fall is:

average velocity (v) = -19.6 m / 2 s = -9.8 m/s

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