Final answer:
The energy of a single photon of light from hydrogen's 656 nm emission is 3.03 x 10^-19 Joules, calculated using the formula E = hc/λ with the given constants for Planck's constant and the speed of light.
Step-by-step explanation:
To calculate the energy of a single photon of light from hydrogen's 656 nm emission, we can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10-34 J·s), c is the speed of light (3.00 x 108 m/s), and λ is the wavelength of the light (656 nm).
First, convert the wavelength from nanometers to meters: 656 nm = 656 x 10-9 m. Next, insert the values into the formula:
E = (6.626 x 10-34 J·s) (3.00 x 108 m/s) / (656 x 10-9 m) = 3.03 x 10-19 J
Therefore, the energy of a single photon of light from hydrogen's 656 nm emission is 3.03 x 10-19 Joules.