Final answer:
The energy of a single photon from hydrogen's 656 nm emission is calculated to be 3.03 x 10^-19 J using the formula E = hc/\lambda with the given values for Planck's constant and the speed of light.
Step-by-step explanation:
The energy of a single photon from hydrogen's 656 nm emission can be calculated using the formula E = \( \frac{hc}{\lambda} \), where E is the energy, h is Planck's constant, c is the speed of light, and \( \lambda \) is the wavelength. Since Planck's constant h is given as 6.626 x 10-34 J\u00b7s and the speed of light c is 3.00 x 108 m/s, we can substitute the values into the formula along with the hydrogen emission wavelength of 656 nm (or 656 x 10-9 m).
Therefore, the energy of a photon is E = \( \frac{(6.626 x 10-34 J\u00b7s)(3.00 x 108 m/s)}{656 x 10-9 m} \) = 3.03 x 10-19 J.