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A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect air resistance)

User Cichy
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1 Answer

10 votes

Answer:

V=14

Step-by-step explanation:

PE=KE

mgh=1/2mv^2

2(9.8)10=1/2(2)v^2

(radical) 196= (radical)v

V=14

User IAmNaN
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