Final answer:
Using the formula for the period of a simple pendulum T = 2π √(l/g), where l is 1.0 m and g is approximately 9.8 m/s², the period for one oscillation is approximately 2.0 seconds. Therefore, the correct answer to the question regarding the period of oscillation for a pendulum with a 1.0 m string length would be choice d.
Step-by-step explanation:
The period of a simple pendulum, like the one described in the question, depends only on the length of the string and the acceleration due to gravity. The formula for the period T of a pendulum is T = 2π √(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. Mass and amplitude, provided the latter is small, do not affect the period. Given that the length l is set to 1.0 m, and assuming the standard acceleration due to gravity g is approximately 9.8 m/s², the theoretical period is approximately 2π √(1.0 m / 9.8 m/s²), or approximately 2π √(0.102 s²), which calculates to around 2.0 seconds for a full swing. Therefore, if a student times 10 swings and divides the total time by 10, the resulting period should be approximately 2.0 seconds per swing, which corresponds to answer choice d.