191k views
3 votes
there is a grapgh with 43 even vertices and 2 odd vertices does this describe a euler path or euler circuit

User Emerita
by
8.2k points

1 Answer

4 votes

Final answer:

A graph with 43 even vertices and 2 odd vertices has an Euler path, according to Euler's theorem, because it has exactly two vertices with odd degrees.

Step-by-step explanation:

When determining whether a graph has an Euler path or an Euler circuit, the degree of the vertices plays a crucial role. In graph theory, an Euler path is a path through a graph that visits every edge exactly once, while an Euler circuit is an Euler path that starts and ends on the same vertex. According to Euler's theorem:

  • A graph will contain an Euler circuit if all vertices have even degree.
  • A graph will contain an Euler path but not an Euler circuit if exactly two vertices have odd degree.

Based on the given graph with 43 even vertices and 2 odd vertices, this configuration describes a graph that has an Euler path. The presence of exactly two vertices with odd degree means the Euler path will start at one of the odd-degree vertices and end at the other odd-degree vertex, since each visit to a vertex will require two edges (one entering and one leaving) except at the start and end points.

User Ellison
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories