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An official playing field ( including end zones) for the indoor Football League has a length 26 yd longer than its width. The perimeter of the rectangular field is 152 yd. Find the length and width of the field.

User Kovge
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1 Answer

4 votes

Explanation:

length = width + 26

perimeter = 2×length + 2×width = 152

now we can use the first identity in the second equation :

2×(width + 26) + 2×width = 152

2×width + 52 + 2×width = 152

4×width = 100

width = 25 yd

length = width + 26 = 25 + 26 = 51 yd

User Ankur Kanoria
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