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29 votes
29 votes
Suppose a paper rocket has a mass of .023 kg. The rocket travels at a velocity of 6.6 m/s and then hits the ground sliding to a stop. If the rocket travels 15 m in coming to a rest what is the work done by friction?

User Baget
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1 Answer

26 votes
26 votes

Answer:

.5 J

Step-by-step explanation:

KInetic Energy of the rocket = 1/2 mv^2 = 1/2 .023 * 6.6 = .5 J

the work of friction has to equal this .5 J

User Sanjoy Kanrar
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2.6k points