Question

You need to divide a class B network into one segment of 110 hosts, one segment of 40 hosts and 2 segments of 20 hosts each. Which combination of subnet masks would you choose to achieve that optimum result?

1/25 segment, 1/26 segment and 2/27 segment
1/26 segment, 1/27 segment and 2/28 segment
1 / 24 segment, 1/25 segment and 2/26 segment
It cannot be done because there is not enough addresses space to accommodate all hosts in a class B networ

Answer 1

To divide a class B network into the desired segments, you would use subnet masks of /25, /26, and /27 to accommodate the number of hosts specified for each segment.

Step-by-step explanation:

In order to divide a class B network into the desired segments, we need to choose the appropriate subnet masks. A subnet mask determines the number of bits used for the network identifier and the host identifier. Let's look at each segment:

1. The segment with 110 hosts requires a subnet mask that can accommodate at least 110 hosts. Since 2^7 (128) is the closest power of 2 that is greater than 110, we would use a /25 subnet mask (255.255.255.128).
2. The segment with 40 hosts requires a subnet mask that can accommodate at least 40 hosts. Since 2^6 (64) is the closest power of 2 that is greater than 40, we would use a /26 subnet mask (255.255.255.192).
3. The two segments with 20 hosts each require a subnet mask that can accommodate at least 20 hosts. Since 2^5 (32) is the closest power of 2 that is greater than 20, we would use a /27 subnet mask (255.255.255.224) for each segment.

Therefore, the combination of subnet masks that would achieve the optimum result is: 1 / 25 segment, 1 / 26 segment, and 2 / 27 segments.