Final answer:
To create a file system with a block size of 64 bytes and 8 blocks using mkfs, use the command mkfs -B 64 -b 8. 1 index node will fit in a block. 4 directory entries will fit in a block. You can create a maximum of 2 directories before the file system is full.
Step-by-step explanation:
To create a file system with a block size of 64 bytes and having a total of 8 blocks using mkfs, you need to run the following command:
mkfs -B 64 -b 8
Within each block, the number of index nodes that will fit depends on the file system. Assuming the file system uses a traditional UNIX-style structure, each index node may vary in size but typically takes up 128 bytes. Therefore, within a 64-byte block, you can fit 64/128 = 0.5 index nodes or 1 index node if rounded up.
In a file system with 64-byte blocks, you can fit 64/16 = 4 directory entries within a block, assuming each entry takes up 16 bytes.
The number of directories that can be created before filling up the file system depends on the allocation of blocks to other file system components, such as index nodes and data blocks. In this case, assuming there are no other components except for directories, you can create a maximum of 8/4 = 2 directories before the file system is full.