Question

Write a 32-bit x86 assembly program that performs the following operations: Part 1: Implement the following arithmetic expression: EAX = -val2 + 7 - val3 + val1 Where: val1 = +8 val2 = - 15 val3 = 20 EAX should be -10?

Answer 1

The question requires creating a 32-bit x86 assembly code that computes a specific arithmetic expression and assigns the result to the EAX register. The calculation is to be based on predefined values, and after the operations, EAX should contain the result of -10.

Step-by-step explanation:

The task is to write a 32-bit x86 assembly program that calculates the result of an arithmetic expression and stores it in the EAX register. The given expression is EAX = -val2 + 7 - val3 + val1, with specific values for val1, val2, and val3:

The expected result in EAX after computation should be -10. Here's a simple assembly program for the task:

section .data
val1 dd 8
val2 dd -15
val3 dd 20
section .text
global _start
_start:
mov eax, [val2] ; EAX = -val2
neg eax ; EAX = -EAX
add eax, 7 ; EAX = EAX + 7
sub eax, [val3] ; EAX = EAX - val3
add eax, [val1] ; EAX = EAX + val1

Note: Since val2 is already negative, moving it to EAX and negating it effectively makes EAX = +val2 at that point, which aligns with the expression requirement. The rest of the operations add and subtract appropriate values to reach the expected result of -10.