Final answer:
A context-free grammar for the language L=aɳbɳ+1 is S → aSb | ab, which produces strings with n occurrences of 'a' followed by n+1 occurrences of 'b' for n ≥ 1.
Step-by-step explanation:
To find an s-grammar (context-free grammar) for the language L= n≥1, we need to define production rules that generate strings containing n occurrences of 'a' followed by n+1 occurrences of 'b' for some n ≥ 1.
Context-Free Grammar (CFG)
A suitable CFG for the language could be:
S → aSb | ab
Here is how the grammar works:
The base case ab caters for the smallest string in the language where n = 1, giving us one 'a' and two 'b's.
The recursive rule S → aSb allows for the induction of any longer string satisfying the condition that for every additional 'a' there will always be an additional 'b'.
This CFG will produce the correct strings as per the defined language, matching the number of 'a's with one more 'b' than the count of 'a's.