Final answer:
FALSE. A function that accepts a structure (not a pointer to a structure) as an argument does not receive a copy of the structure. Instead, the function receives a pointer to the structure, which allows it to modify the original structure.
Step-by-step explanation:
FALSE
A function that accepts a structure (not a pointer to a structure) as an argument does not receive a copy of the structure. Instead, the function receives a pointer to the structure, which allows it to modify the original structure. If a copy of the structure is needed, it can be explicitly created within the function. Here's an example:
struct Student {
int id;
char name[50];
};
void updateStudent(struct Student s) {
s.id = 1001;
strcpy(s.name, "John");
}
int main() {
struct Student myStudent;
myStudent.id = 999;
strcpy(myStudent.name, "Jane");
updateStudent(myStudent);
printf("ID: %d, Name: %s", myStudent.id, myStudent.name);
return 0;
}
In the example, the updateStudent function does not make a copy of the Student structure. Instead, it receives a pointer to the original structure, allowing it to modify the values. If the function made a copy, the changes would not affect the original structure.