Question

Show what is produced by the following Java code

Node myList new Node("B");
myList.next = new Node("C");
myList.next.next = new Node ("D");
• Node p = new Node("A", myList);
Node b p.next; =
• Node c = b.next;
b.next new Node("B");

Answer 1

The Java code creates a linked list of Node objects with the final list order being "A", "B", "B", "C", "D".

Step-by-step explanation:

The Java code provided is creating a linked list of Node objects. Here is the breakdown of what happens when the code executes: A new Node with value "B" is created and assigned to myList. Next, a new Node with value "C" is attached as the next node of myList.

Another new Node with value "D" is attached as the next node of the Node containing "C". A new Node with value "A" is created, and it's next property is set to myList, inserting it at the beginning of the list. b is set to the second Node of the list, which contains the value "B".

c is set to the third Node of the list, which is the one containing "C". The next Node after b is replaced with a new Node containing "B", effectively inserting a duplicate "B" value between the "A" and "C" Nodes. The final list order is "A", "B", "B", "C", "D".