Final Answer:
```java
public static <T extends Comparable<T>> int checkOrder(T t1, T t2, T t3, T t4) {
if (t1.compareTo(t2) < 0 && t2.compareTo(t3) < 0 && t3.compareTo(t4) < 0) {
return -1; // Ascending order
} else if (t1.compareTo(t2) > 0 && t2.compareTo(t3) > 0 && t3.compareTo(t4) > 0) {
return 1; // Descending order
} else {
return 0; // Unordered
}
}
```
Step-by-step explanation:
The provided static method, `checkOrder`, takes four parameters of type T, where T is a bounded generic type extending Comparable. The method utilizes the compareTo method, inherent to the Comparable interface, to compare the relationships between the parameters. For ascending order, it checks if each subsequent element is greater than its predecessor. For descending order, it checks the reverse. The method returns -1 for ascending order, 1 for descending order, and 0 for unordered.
To elaborate, the comparison uses the compareTo method's result, which returns a negative value if the invoking object is less than the argument, zero if equal, and a positive value if greater. The logical combinations ensure that the method accurately identifies the order relationship between the parameters. The generic nature of the method allows it to handle various data types, ensuring flexibility and reusability.
The provided test code demonstrates the functionality of the `checkOrder` method with different data types, confirming its ability to correctly determine the order relationship between the parameters, be it ascending, descending, or unordered. This implementation aligns with best practices in Java generics and leverages the Comparable interface for effective comparison.