Final answer:
The correct statement about Type 1 fucosidosis is that (C) Ff individuals produce enough of the enzyme α-1-fucosidase to prevent the disease, because having one functioning allele is sufficient. Two carriers have a 25% chance of having a child with the condition.
Step-by-step explanation:
Type 1 fucosidosis is a rare human disease caused by a genetic defect in the enzyme α-1-fucosidase which is crucial for the breakdown of fucose. This disease is inherited in an autosomal recessive manner, meaning that an individual must inherit two copies of the defective gene, one from each parent, to exhibit the condition.
The correct statement about Type 1 fucosidosis is that C. Ff individuals make enough α-1-fucosidase to break down fucose and do not exhibit the condition. This is because the presence of one functioning allele (F) produces sufficient enzyme to prevent the symptoms of the disease. These Ff individuals are carriers of the disease but do not show signs of it. If two carriers (Ff) have a child, there is a 25% chance that the child will inherit two defective genes (ff), a 50% chance that the child will also be a carrier (Ff), and a 25% chance of the child inheriting normal genes (FF).