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X(t)=x₀e− γ/²ᵗ cos(ωt+ϕ)

Plot this solution for 0≤t≤6, with the parameters x 0=1, ω=2π, and ϕ=−π/2, for three different damping rates γ=0,γ=0.5 and γ=3. Plot all the curves on the same axes in different colours so they can be compared.

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Final answer:

To plot x(t) for different damping rates, substitute the given values and calculate the positions for each time interval.

Step-by-step explanation:

To plot the function x(t) = x₀e- γ/²ᵗ cos(ωt+ϕ) for different damping rates, we can use the given parameters. Let's calculate the values of x(t) for each damping rate and plot them on the same axes:

For γ = 0, the function becomes x(t) = x₀ cos(ωt+ϕ). This is a simple harmonic motion without any damping, resulting in a cosine function. We can plot this using the given values of x₀ = 1, ω = 2π, and ϕ = -π/2.

For γ = 0.5 and γ = 3, we use the formula x(t) = x₀e- γ/²ᵗ cos(ωt+ϕ) with the same given values. We can calculate the values of x(t) for each time interval and plot them on the same axes, using different colors for each damping rate.

User Gregory Arenius
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