Final answer:
To answer the student's query in Mathematics, we need to create a recursive function that calculates the sum of squared odd digits of an integer. This involves checking each digit, squaring it if odd, and adding it to a sum which is then returned if no digits are left. The example provided, 9234, results in 90.
Step-by-step explanation:
The student's question involves creating a recursive function to calculate the sum of the squared odd digits of a positive integer. This problem falls into the category of Mathematics, and more specifically, it deals with concepts such as recursive functions, operations on digits, and understanding of squaring of exponentials.
To solve this problem, the function will take an integer as the input and proceed to check each digit. If the digit is odd, it will square the digit and add it to a running total. This process will continue recursively by reducing the number by one digit (by dividing by 10) until the number is 0, at which point the function will return the total sum of squared odd digits. If there are no odd digits, the function will return 0.
An example provided was the number 9234, which would have the sum of squared odd digits as 92 + 32 = 81 + 9 = 90.
- Divide the number by 10 to reduce it to the next digit.
- Calculate the square of the odd digits.
- Accumulate the square in a sum recursively.
- Return the sum or 0 if no odd digits are present.