The average acceleration of the 3 kg block is 4 m/s^2. According to Newton's third law, two equal and opposite forces do not cancel each other out because they act on different objects. The acceleration of the system is 45N / m. T2 cannot be calculated without knowing the value of m.
3. When a spring is compressed between two blocks, it exerts a force on both blocks. According to Newton's third law, the force exerted by the spring on the 2 kg block is equal in magnitude but opposite in direction to the force exerted by the 2 kg block on the spring. Since the 2 kg block has an average acceleration of 6 m/s^2 when the spring acts on it, we can use Newton's second law (F = ma) to find the force exerted by the spring on the 2 kg block:
F = m * a
F = 2 kg * 6 m/s^2
F = 12 N
Since the force exerted by the spring on the 2 kg block is equal to the force exerted by the 2 kg block on the spring, the force exerted by the 2 kg block on the spring is also 12 N.
Now, let's consider the 3 kg block. Since the spring is compressed between the blocks, the force exerted by the 3 kg block on the spring will also be 12 N, according to Newton's third law.
To find the average acceleration of the 3 kg block, we can again use Newton's second law:
F = m * a
12 N = 3 kg * a
a = 4 m/s^2
Therefore, the average acceleration of the 3 kg block is 4 m/s^2.
4. According to Newton's third law, two equal and opposite forces do not cancel each other out because they act on different objects. When two objects interact, they exert forces on each other that are equal in magnitude but opposite in direction. However, these forces act on different objects and have different effects.
For example, if you push against a wall, the wall exerts an equal and opposite force on you. These forces do not cancel each other out because they act on different objects. The force you exert on the wall prevents you from moving forward, while the force from the wall prevents it from collapsing. The forces are balanced in the sense that they have equal magnitudes, but they do not cancel each other out.
5. To solve this problem, we can use the following equations:
F = ma
T1 - T2 = ma
where:
* F is the net force on the system
* m is the total mass of the system
* a is the acceleration of the system
* T1 is the tension in string 1
* T2 is the tension in string 2
We are given that T1 is 45N. We need to find T2 and the acceleration of the system.
To find T2, we can use the second equation above:
T1 - T2 = ma
Substituting the given values, we get:
45N - T2 = ma
We do not know the values of m and a yet, so we cannot solve for T2 directly.
To find the acceleration of the system, we can use the first equation above:
F = ma
We know that the net force on the system is equal to the tension in string 1, T1. This is because there is no other external force acting on the system.
F = T1
Substituting the given value, we get:
T1 = ma
45N = ma
a = 45N / m
Now that we know how to calculate the acceleration of the system, we can substitute it back into the second equation to find T2:
T1 - T2 = ma
T1 - T2 = 45N / m
T2 = T1 - 45N / m
We still do not know the value of m, so we cannot solve for T2 directly.
However, we can see that the acceleration of the system is 45N / m.