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Using C++

1. Can someone show me an example and explain the difference between tagged and untagged structures, and then show me an example of a nested structure
can you show me a combination of a structures and arrays. How would that work?

1 Answer

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Final answer:

Tagged structures have a name associated with them and can be used to declare variables, while untagged structures can only define variables within a program. Nested structures allow you to group data in a hierarchical manner. Arrays of structures allow you to store multiple instances of the same structure.

Step-by-step explanation:

Tagged and Untagged Structures:

In C++, structures are used to group related data together. A tagged structure is a structure that has a name, or a tag, associated with it. This tag allows you to declare variables of that structure type. An untagged structure, on the other hand, does not have a name associated with it and can only be used to define variables within a program

A nested structure is a structure that is defined within another structure. It allows you to group data in a hierarchical manner. Here's an example:

#include <iostream>

struct Person {
std::string name;
int age;
};

struct Address {
std::string street;
std::string city;
std::string state;
};

struct Employee {
Person personalInfo;
Address addressInfo;
};

int main() {
Employee employee;
employee.personalInfo.name = "John Doe";
employee.personalInfo.age = 25;
employee.addressInfo.street = "123 Main St";
employee.addressInfo.city = "New York";
employee.addressInfo.state = "NY";

return 0;
}



Combination of Structures and Arrays:

In C++, you can use arrays of structures to store multiple instances of the same structure. Here's an example:

#include <iostream>

struct Student {
std::string name;
int age;
};

int main() {
const int SIZE = 3;
Student students[SIZE];

students[0].name = "Alice";
students[0].age = 18;

students[1].name = "Bob";
students[1].age = 19;

students[2].name = "Charlie";
students[2].age = 20;

return 0;
}

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