Final answer:
The voltage across the battery in a series circuit with a 12 ohm and a 28 ohm resistor, and a current of 15mA, is determined using Ohm's Law and calculating the total resistance. By applying the law (V = IR), the battery voltage is found to be 0.6 volts.
Step-by-step explanation:
The question is about determining the voltage across the battery in a series circuit that includes a 12-ohm and a 28-ohm resistor, with a current flow of 15mA. To find the voltage of the battery, we use Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the total resistance. First, we need to find out the total resistance (R) in the circuit by adding the individual resistances since they are in series:
- Rtotal = R1 + R2 = 12 Ω + 28 Ω = 40 Ω
Next, we convert the current from milliamperes to amperes:
- I = 15 mA = 15 x 10-3 A = 0.015 A
Now, we can calculate the voltage across the battery:
- V = I x Rtotal = 0.015 A x 40 Ω = 0.6 V
Therefore, the battery voltage for the given circuit is 0.6 volts.