Question

Consider a bus-topology network with five stations. A reservation access method is used. Each station has infinite data to transmit. Each reservation slot has 10 microseconds (note that 1 microsecond = 10 second). For each station, one data transmission sends 1000 bits. The transmission rate over the medium is 10 Mbps. For a station, which is its throughput (in unit "Mbps")?

Answer 1

To calculate the throughput for a station, divide the transmission rate (10 million bits per second) by the number of stations, giving a throughput of 2 Mbps per station.

Step-by-step explanation:

To calculate the throughput for a station in a bus-topology network using a reservation access method, we need to determine how many bits can be sent in a given period of time. In this scenario, each reservation slot is 10 microseconds long, and the transmission rate is 10 Mbps (megabits per second). Since one data transmission sends 1000 bits, we can calculate the throughput for each station.

First, convert the transmission rate to bits per microsecond:

1. 10 Mbps = 10 million bits per second = 10,000 bits per microsecond.

Next, we calculate the number of bits that can be sent in one reservation slot:

1. 10,000 bits/μs * 10 μs = 100,000 bits per reservation slot.

Given that each station has infinite data to transmit and each data transmission is 1000 bits, we can calculate the number of data transmissions per slot:

1. 100,000 bits / 1000 bits per transmission = 100 transmissions per reservation slot.

Since there are five stations, we must divide the total number of transmissions by the number of stations to get the throughput per station:

1. 100 transmissions per slot / 5 stations = 20 transmissions per station per slot.

Finally, we convert transmissions back into bits to find the throughput in Mbps:

1. 20 transmissions * 1000 bits per transmission = 20,000 bits
2. Throughput per station: 20,000 bits per 10 μs slot = 2 Mbps.

Therefore, the throughput for each station is 2 Mbps.