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Using list comprehension, define a function named create_multiples_of_3(maximum) which takes an integer maximum as a parameter and returns a list of positive integers which are multiples of 3 and are less than maximum.

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Final answer:

Using list comprehension, a function named create_multiples_of_3(maximum) can be defined in Python to return a list of positive integers that are multiples of 3 and are less than the given maximum.

Step-by-step explanation:

A function named create_multiples_of_3(maximum) can be defined using list comprehension in Python to return a list of positive integers that are multiples of 3 and are less than the given maximum. Here is an example:

def create_multiples_of_3(maximum):
return [x for x in range(1, maximum) if x % 3 == 0]

This function uses list comprehension to generate a list of numbers from 1 to 'maximum', but only includes those numbers that are divisible by 3. The result is a list of multiples of 3 that are less than 'maximum'.

The function 'create_multiples_of_3' in Python can be defined using list comprehension to generate a list of positive multiples of 3 less than a given maximum. This is achieved by using a range starting from 3 with a step value of 3, ensuring each number in the list is a multiple of 3.

To define a function named create_multiples_of_3 using list comprehension in Python, you can use the following approach. This function will take an integer maximum as a parameter and return a list of positive integers that are multiples of 3 and are less than the specified maximum.

def create_multiples_of_3(maximum):
return [x for x in range(3, maximum, 3)]

This list comprehension starts at 3 and increments by 3 all the way up to but not including the maximum value. Notably, the start value is 3 because 0 is a multiple of every number, but the requirement here is for positive integers. Each iteration of the loop implicitly checks if the number is a multiple of 3, as the step value in the range is set to 3.

To use this function, simply call it with the desired maximum value:

print(create_multiples_of_3(10)) # Output will be [3, 6, 9]

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