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2Zn(NO3)2 number of nitrogen atoms

User Olmo
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Answer: The chemical formula 2Zn(NO3)2 represents two moles of zinc nitrate. Within one mole of zinc nitrate, there are two nitrate ions (NO3^-) per formula unit.

Therefore, to find the number of nitrogen atoms present in 2 moles of zinc nitrate (2Zn(NO3)2):

1 mole of zinc nitrate contains 2 moles of nitrate ions (NO3^-).

1 mole of nitrate ions contains 1 mole of nitrogen atoms (N).

So, for 2 moles of zinc nitrate:

2 moles Zn(NO3)2 * 2 moles NO3^-/mole Zn(NO3)2 * 1 mole N/mole NO3^- = 4 moles of nitrogen atoms.

Thus, there are 4 moles of nitrogen atoms in 2 moles of zinc nitrate, which corresponds to
\(4 * 6.022 * 10^(23)\) nitrogen atoms (using Avogadro's number,
\(6.022 * 10^(23)\) atoms/mol).

User Suraken
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