Question

Consider three different raster systems with resolutions of 640 by 400, 1280 by 1024, and 2560 by 2048. What size frame buffer (in bytes) is needed for each of these systems to store 12 Bits per pixel and for 24 Bits?

Answer 1

aFinal answer:

To calculate the frame buffer size, multiply the resolution by the color depth (in bits per pixel) and then divide by 8 to get the size in bytes. For 12 Bits per pixel, the sizes are 384000, 1966080, and 7864320 bytes for the respective resolutions. For 24 Bits per pixel, the sizes are 768000, 3932160, and 15728640 bytes.

Step-by-step explanation:

The student's question pertains to the calculation of frame buffer size needed for different resolutions and color depths in a raster system, specifically asking for sizes calculated for 12 Bits per pixel and 24 Bits.

To calculate the frame buffer size, you multiply the resolution (number of pixels) by the color depth (bits per pixel) and then divide by 8 to convert bits to bytes:

• Size in bytes = (Pixels Width × Pixels Height × Bits per Pixel) / 8

For 12 Bits per pixel:

• 640 x 400 resolution: (640 × 400 × 12) / 8 = 384000 bytes
• 1280 x 1024 resolution: (1280 × 1024 × 12) / 8 = 1966080 bytes
• 2560 x 2048 resolution: (2560 × 2048 × 12) / 8 = 7864320 bytes

For 24 Bits per pixel:

• 640 x 400 resolution: (640 × 400 × 24) / 8 = 768000 bytes
• 1280 x 1024 resolution: (1280 × 1024 × 24) / 8 = 3932160 bytes
• 2560 x 2048 resolution: (2560 × 2048 × 24) / 8 = 15728640 bytes

Note that 1 byte is equal to 8 bits and these calculations assume that no additional memory is used for other purposes such as additional buffering or overhead associated with the frame buffer.