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Write assembly language codes that will display the output given below. Clear the entire screen and display it at row 1 , column 1 . You may use any attribute. Use functions/services and loop operation

0123456789
012345678
01234567
0123456
012345
01234
0123
012
01
0
By using dosbox

User Kiera
by
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1 Answer

6 votes

Final answer:

To display the given output using assembly language, you can clear the screen using DOS interrupt 21h and then use nested loops to display the numbers in a specific pattern.

Step-by-step explanation:

To clear the entire screen and display the given output using assembly language, you can use the following code:

  1. Call the DOS interrupt 21h to clear the screen. This can be done by setting the AH register to 06h and AL register to 00h.
  2. Use a loop to display the output in a pattern. Start with a loop counter that represents the number of rows.
  3. Inside the loop, use another loop to display each row. Start with a counter that represents the number of elements in the row.
  4. Inside the inner loop, use the DOS interrupt 21h to display the numbers, one by one, at the desired row and column.

Here is an example of the code:

MOV AH, 06h
MOV AL, 00h
INT 10h
MOV CX, 10
MOV DX, 1
outer_loop:
MOV BX, CX
inner_loop:
PUSH BX
MOV AH, 02h
MOV DL, 30h
ADD DL, BL
ADD DL, '0'
INT 21h
POP BX
INC BX
LOOP inner_loop
DEC CX
JNZ outer_loop
User Andy Mell
by
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