Question

Rewrite this class so that it implements the Comparable interface so that AAA objects can be compared. Letting X and Y be two AAA objects, you will compare then as follows: X>Y when X has a larger area (length width); when their areas are the same, X>Y when X 's name is longer than Y 's name; when they have the same area and name lengths, X>Y when X has more friends than Y. Finally, X=Y when they have the same area and name lengths. Your rewritten class must be a concrete class. To save time, you do not need to rewrite the attributes in your class (but everything else must be present).

Answer 1

Here the rewritten format:

public class AAA implements Comparable<AAA> {

// Attributes not rewritten for brevity

(at)Override

public int compareTo(AAA other) {

int areaComparison = Double.compare(this.getLength() * this.getWidth(), other.getLength() * other.getWidth());

if (areaComparison != 0) {

return areaComparison;

}

int nameLengthComparison = Integer.compare(this.getName().length(), other.getName().length());

if (nameLengthComparison != 0) {

return nameLengthComparison;

}

return Integer.compare(this.getFriends(), other.getFriends());

}

}

Step-by-step explanation:

The rewritten `AAA` class implements the `Comparable` interface with the type `AAA`, allowing objects of this class to be compared based on the specified criteria. The `compareTo` method calculates the comparison between two `AAA` objects according to their area (length * width), name lengths, and number of friends, returning the appropriate comparison result as per the given rules. It first compares the areas of the objects; if they're equal, it moves on to compare name lengths, and if those are also equal, it compares the number of friends. Finally, it returns the comparison result according to the defined criteria.