Question

Given the class SampleD0 defined in example M9, what is the output of the following program? /*---------------------------------------------Program--------------------------------------------------------------*/ int Main( ) { SampleD0 obj1( 2 ), obj2( 3 ), obj3( 5 ); cout << obj1.getValue( ) + obj2.getValue( ) + obj3.getValue( ); return 0; }

Answer 1

Without the definition of the class SampleD0 and its method getValue(), it is impossible to determine the exact output. If getValue() returns the constructor value, the output would be the sum of those values, which is 10.

Step-by-step explanation:

The question is asking about a C++ programming scenario where a class named SampleD0 is mentioned without its definition provided. The main function creates three objects of this class (obj1, obj2, and obj3) with the values 2, 3, and 5 passed to their respective constructors. It then proceeds to call a member function getValue() on each object and adds the results together, outputting them to the console.

Without the implementation details of the SampleD0 class and the getValue() function, we cannot determine the exact output of the program. However, we can infer that if the getValue() function returns the value passed to the constructor, the output would be the sum of those values, which is 2 + 3 + 5 = 10.

It is essential to have access to the full definition of the SampleD0 class and the getValue() function to provide a precise answer.