The line passes through the y-axis at the point (0, 4). The slope of the line is 2, calculated from two points on the line. The linear equation representing the line is y = 2x + 4.
To find the point where the line crosses the y-axis, we can calculate the y-intercept (b) by extending the line to where x=0.
From the two given points (-3,-2) and (-1,2), we first determine the slope (m) of the line using the formula m = (y2 - y1) / (x2 - x1), which in this case is m = (2 - (-2)) / (-1 - (-3)) = 4 / 2 = 2.
To obtain the equation of the line in the form y = mx + b, we use one point and the slope to solve for b.
For example, using the point (-1, 2): 2 = 2(-1) + b, which simplifies to b = 4.
Therefore, the equation is y = 2x + 4, indicating the line crosses the y-axis at the point (0, 4).
The probable question may be:
In the graph the line is passing from point (-3,-2) and (-1,2)
1. WHAT IS THE POINT WHERE THIS LINE CROSSES THE Y-AXIS?
2. EXPLAIN HOW YOU WOULD FIND THE SLOPE OF THIS LINE.
3. WHAT IS THE Y = MX + B EQUATION OF THIS LINE?