Question

Consider the balanced equation for the combustion of benzene, C₆H₆

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O What molar ratio will appear when calculating the amount of O2 needed to react with a given amount of C₆H₆?
a. 15molO₂ / 2mol C₆H₆
b. 1mol O₂ / 1mol C₆H₆
c. 12mol CO₂ / 2mol C₆H₆

Answer 1

The molar ratio for the amount of O2 needed to react with C6H6 according to the provided chemical equation is 15 mol O2 / 2 mol C6H6. This ratio is used to calculate the mass of CO2 and H2O formed from the combustion of a given mass of benzene.

Step-by-step explanation:

The molar ratio to calculate the amount of O2 needed to react with a given amount of C6H6 is derived from the balanced chemical equation for the combustion of benzene: 2C6H6 + 15O2 → 12CO2 + 6H2O. Using this equation, we find that the molar ratio is 15 mol O2 / 2 mol C6H6.

When answering the question regarding how much CO2 and H2O will be produced from the combustion of 10.00 mg of benzene, it is important to first convert the mass of benzene to moles by using its molar mass, then use the stoichiometry of the balanced equation to find the masses of products formed.