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Aluminum has a density of 2.70 g/cm³. What is the mass (g) of aluminum foil that has a volume of 48.9 cm³?

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Final answer:

To find the mass of aluminum foil with a volume of 48.9 cm³, multiply the volume by its density, 2.70 g/cm³, resulting in a mass of approximately 132.03 grams.

Step-by-step explanation:

The mass of aluminum foil can be calculated by multiplying its volume by its density. The density of aluminum is a known constant 2.70 g/cm³. Therefore, to find the mass of aluminum foil with a volume of 48.9 cm³, we use the formula:

Mass (g) = Density (g/cm³) × Volume (cm³)

By substituting the given values into the formula, we obtain:

Mass (g) = 2.70 g/cm³ × 48.9 cm³

The resulting mass of the aluminum foil is:

Mass (g) = 132.03 g

This calculation shows that a piece of aluminum foil with a volume of 48.9 cm³ will have a mass of approximately 132.03 grams.

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