Final answer:
From 280 grams of H2, we can produce approximately 93.3 moles of NH3, as per the stoichiometry of the balanced chemical equation N2 + 3H2 → 2NH3.
Step-by-step explanation:
To determine how many moles of NH3 can be produced from 280 grams of H2, we first need to calculate the moles of H2 using its molar mass (approximately 2.02 g/mol).
Moles of H2 = 280 g ÷ 2.02 g/mol = 138.61 moles of H2
According to the balanced chemical equation N2 + 3H2 → 2NH3, 3 moles of H2 produce 2 moles of NH3. Thus, we can set up a proportion.
Moles of NH3 = (2 moles NH3 ÷ 138.61 moles H2) ÷ 3 moles H2 = 92.40 moles of NH3
Therefore, the closest answer to the number of moles of NH3 produced from 280 grams of H2 is answer b. 93.3 moles.