Final answer:
There are 142.49 grams of glucose in 911.47 mL of the 15.63 %(m/v) glucose-water solution.
Step-by-step explanation:
To find the number of grams of glucose in the solution, we can use the formula:
grams of solute = volume of solution (mL) * percent (m/v)
Plugging in the values from the question, we have:
grams of glucose = 911.47 mL * 15.63% = 142.49 g
Therefore, there are 142.49 grams of glucose in 911.47 mL of the solution.