Question

Set B's lower nibble to A's lower nibble, and B's upper nibble

to 2
Use C code, please
#include "RIMS.h"
int main() {
while(1) {
/* Your solution goes here */
}
return 0;
}

Answer 1

In C code, you can set B's lower nibble to A's lower nibble and B's upper nibble to 2 using bitwise operations.

Step-by-step explanation:

In C code, you can set B's lower nibble (four bits) to A's lower nibble by using bitwise operations. You can do this by ANDing B with the mask 0xF0 to keep the upper nibble intact and ANDing A with the mask 0x0F to keep the lower nibble intact. Then, you can OR the results together to combine the upper nibble of B and the lower nibble of A.

To set B's upper nibble to 2, you can use the bitwise OR operation with the mask 0x0F to keep B's lower nibble intact and OR with 0x20 to set the upper nibble to 2.

Here is the code that accomplishes these tasks:

#include "RIMS.h"
ten main() {
while(1) (A & 0x0F));
B = ((B & 0x0F)
return 0;
}