Final answer:
In Java, you can use the Bubble sort algorithm to sort an array of Integers by the number of digits in the Integer, comparing the number of digits and swapping as necessary. Provide user input for the array and call the bubbleSort method to sort it.
Step-by-step explanation:
In Java, you can use the Bubble sort algorithm to sort an array of Integers by the number of digits in the Integer. To do this, you would compare the number of digits in each pair of Integers and swap them if necessary. Here's an example implementation:
public static void bubbleSort(Integer[] arr) {
int n = arr.length;
for (int i = 0; i < n-1; i++) {
for (int j = 0; j < n-i-1; j++) {
int numDigits1 = String.valueOf(arr[j]).length();
int numDigits2 = String.valueOf(arr[j+1]).length();
if (numDigits1 < numDigits2 || (numDigits1 == numDigits2 && arr[j] > arr[j+1])) {
int temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
}
}
Once the array is sorted, you can iterate over it to print the elements in the desired order. Give user input for the array and call the bubbleSort method to sort it.
The task is to sort an array of integers with Java's Bubble sort based first on the number of digits (largest to smallest) and then by value (smallest to largest) when the number of digits is identical. The number of digits for each integer can be assessed by converting the integer to a string and getting the length of the string.
The question involves sorting an array of integers using Bubble sort based on the number of digits and then by value using Java. To solve this, we first compare the number of digits of adjacent integers. If they differ, we swap them to order from the largest number of digits to the smallest. If they have the same number of digits, we compare their values and sort them in ascending order. Bubble sort involves repeatedly stepping through the list, comparing adjacent elements and swapping them if they are in the wrong order.
This process is repeated until the array is sorted. The length of an integer can be determined by converting it to a string and checking the string's length. Thus, in Java, we could utilize String.valueOf(integer).length() to find out the number of digits.
Given the provided sample array '15 78 987 2 7632 12398', after sorting based on the number of digits and then by value when the number of digits is the same, the expected output will be '12398 7632 987 78 2'. Similarly, given the sample array '26 77 23 5 1 7 101', the expected output will be '101 23 77 1 5 7'.