Question

The initial state of a NOR-gate latch is Q=0 and the following pulses are applied

i) A pulse of width 3 tpd is applied to S after 2 tpd
ii) A second pulse of width 1 tpd is applicd to R after a duration of 7 tpd
iii) A third pulse of width 3 tpd is applied to S after a duration of 13 tpd
iv) Finally, two pulses of with 3 tpd are applied simultaneously to R and S after a duration of 18 ipd
Assuming gates with zcro rise and fall times with propagation delays of 1 tpd each, illustrate the resultizg transitions on a timing diagram. Use the graph paper provided

Answer 1

The NOR-gate latch transitions are as follows:

- i) Q transitions from 0 to 1 after 2 tpd when a pulse of width 3 tpd is applied to S.

- ii) Q transitions from 1 to 0 after 7 tpd when a pulse of width 1 tpd is applied to R.

- iii) Q transitions from 0 to 1 after 13 tpd when a pulse of width 3 tpd is applied to S.

- iv) Q transitions from 1 to 0 after 18 tpd when simultaneous pulses of width 3 tpd are applied to R and S.

Step-by-step explanation:

In the initial state, the NOR-gate latch has Q=0. When a pulse of width 3 tpd is applied to S after 2 tpd (i), Q transitions to 1. Subsequently, when a pulse of width 1 tpd is applied to R after 7 tpd (ii), Q transitions back to 0. After that, when a pulse of width 3 tpd is applied to S after 13 tpd (iii), Q transitions to 1 again. Finally, simultaneous pulses of width 3 tpd are applied to R and S after 18 tpd (iv), causing Q to transition back to 0.

The transitions are determined by the NOR-gate latch logic, where Q is set to 1 when S is pulsed, and Q is reset to 0 when R is pulsed. The timing diagram illustrates these transitions over time, showing the dynamic behavior of the NOR-gate latch as different pulses are applied. The propagation delays and pulse widths play a crucial role in determining the precise timing of each transition, ensuring accurate representation on the timing diagram.