Final answer:
The maximum file size in the given Unix file system is approximately 64.13 GB. The largest file size that does not require any indirect blocks is 6 KB.
Step-by-step explanation:
In a traditional Unix file system with the given specifications, the maximum file size can be calculated as follows: 12 direct blocks * 512 bytes/block = 6144 bytes = 6 KB. 1 single-indirect block * 512 bytes/block * 512 bytes/block = 262,144 bytes = 256 KB. 1 double-indirect block * 512 bytes/block * 512 bytes/block * 512 bytes/block = 134,217,728 bytes = 128 MB. 1 triple-indirect block * 512 bytes/block * 512 bytes/block * 512 bytes/block = 68,719,476,736 bytes = 64 GB. Adding up the maximum sizes for each block type, we get a total of 64 GB + 128 MB + 256 KB + 6 KB, which is approximately 64.13 GB. Therefore, the maximum file size is 64.13 GB. The largest file size that does not require any indirect blocks can be calculated as follows: 12 direct blocks * 512 bytes/block = 6144 bytes = 6 KB. Therefore, the largest file size that does not require any indirect blocks is 6 KB.
To calculate the maximum file size on a traditional Unix file system with inodes containing 12 direct blocks, 1 single-indirect, 1 double-indirect, and 1 triple-indirect block, we must sum the data that can be addressed by each type of block. With a block size of 512 bytes and each disk block address taking up 32 bits (4 bytes), we consider the following: Direct blocks: 12 blocks * 512 bytes/block = 6,144 bytes. Single-indirect block: (512 bytes / 4 bytes/address) * 512 bytes/block = 65,536 bytes. Double-indirect block: ((512 bytes / 4 bytes/address) * (512 bytes / 4 bytes/address)) * 512 bytes/block = 33,554,432 bytes. Triple-indirect block: ((512 bytes / 4 bytes/address) * (512 bytes / 4 bytes/address)) * (512 bytes / 4 bytes/address)) * 512 bytes/block = 17,179,869,184 bytes. Adding these figures up gives us the maximum file size: 6,144 + 65,536 + 33,554,432 + 17,179,869,184 = 17,214,495,296 bytes. Dividing by 1,024 repeatedly to convert bytes to kilobytes and then to megabytes: 17,214,495,296 bytes / 1,024 = 16,816,304 KB / 1,024 = 16,426 MB / 1,024 ≈ 16 GB. So, the maximum file size would be approximately 16 GB (rounded to the nearest MiB). To find the largest file size that does not require any indirect blocks, we only consider the direct blocks: 12 blocks * 512 bytes/block = 6,144 bytes / 1,024 = 6 KB. Therefore, the largest file size not requiring any indirect blocks is 6 KB (rounded to the nearest KiB).