Final answer:
To find the three-digit positive integers where the sum of the cubes of the decimal digits is equal to the number itself, you can iterate through all three-digit numbers, extract the decimal digits, and check if their cubes sum up to the original number.
Step-by-step explanation:
To find the three-digit positive integers where the sum of the cubes of the decimal digits is equal to the number itself, we can iterate through all three-digit numbers, extract the decimal digits, and check if their cubes sum up to the original number. Here's an example of how this program can be implemented in Python:for num in range(100, 1000): digit1 = num % 10 digit2 = (num // 10) % 10 digit3 = num // 100 if digit1**3 + digit2**3 + digit3**3 == num: print(num)This code will print out all the three-digit positive integers that satisfy the given condition.The question is asking to write a program that finds all three-digit positive integers which meet a specific criterion: the sum of the cubes of each of its decimal digits equals the number itself.
Such numbers are special in mathematical contexts, commonly known as Armstrong numbers or Narcissistic numbers.Here is a simple example of how one might write a program in Python:for num in range(100, 1000): sum_of_cubes = sum(int(digit) ** 3 for digit in str(num)) if num == sum_of_cubes:print(num)This program will output any three-digit numbers for which the condition is true.