Question

Pls send the code (using "Assembly Programming Language") for below question: Assume that AX=2,BX=3,CX=4. Now find the value of the expression, 2AX+3BX−4(CX−AX) and show it in DX.

Answer 1

The code provided calculates the value of the expression 2AX + 3BX - 4(CX - AX) in Assembly language, where AX, BX, and CX are registers with initial values 2, 3, and 4 respectively. The result of the expression is stored in the DX register.

Step-by-step explanation:

The subject is asking for Assembly code to calculate the value of the expression 2AX + 3BX - 4(CX - AX) and store the result in DX. The initial values for AX, BX, and CX are given as 2, 3, and 4 respectively. To solve this in Assembly, one approach is to perform the operations step by step. Here's a simple code snippet:

MOV AX, 2 ; Load AX with value 2
MOV BX, 3 ; Load BX with value 3
MOV CX, 4 ; Load CX with value 4
MOV DX, 0 ; Clear out DX to use for the result

; Calculate 2 * AX
SHL AX, 1 ; AX = AX * 2
ADD DX, AX ; DX = DX + AX

; Calculate 3 * BX
MOV AX, BX ; Move BX to AX for multiplication
SHL AX, 1 ; AX = AX * 2
ADD AX, BX ; AX = AX + BX
ADD DX, AX ; DX = DX + AX

; Calculate 4 * (CX - AX original)
MOV AX, 2 ; Restore original value of AX
SUB CX, AX ; CX = CX - AX
SHL CX, 2 ; CX = CX * 4
SUB DX, CX ; DX = DX - CX

This code segment calculates each term of the expression and updates DX with the intermediate results. The use of the SHL instruction is for multiplying by powers of 2 (since SHL is equivalent to multiplying by 2).

Answer 2

The value of the expression
`\(2AX + 3BX - 4(CX - AX)\)` in Assembly language, with given register values (AX=2, BX=3, CX=4), is stored in the DX register.

Step-by-step explanation:

In Assembly language, each line of code corresponds to a specific instruction. The `MOV` instruction is used to move values into registers. The `IMUL` instruction performs signed multiplication, and the `SUB` and `ADD` instructions handle subtraction and addition, respectively.

Given the expression
`\(2AX + 3BX - 4(CX - AX)\)`, the code initializes the values in the AX, BX, and CX registers. The IMUL instruction is used to perform the multiplications, and the result is stored in the corresponding registers. The SUB and ADD instructions handle the subtraction and addition operations as per the expression.

Finally, the result of the expression is stored in the DX register, representing the outcome of the calculations. This assembly code provides a step-by-step execution of the mathematical operations specified in the expression, considering the initial values in AX, BX, and CX.