Question

This is for a unit test where I had to pick two things from Amazon to buy, and if it was going to be a system of equations or inequalities. I don't know what that means so pls tell me which one too.

part 1) present 1 is a $26.99 seal plush and present 2 is a $35.99 yeti plush. the variables I'm using are x and y.

part 2) You must buy at least 20 items of present 1. remember that you have at most 1000 to spend. write your system.

step 3) since there are 60 total employees, what is one possible solution to the scenario if you buy at least, one present for each employee? Explain your thinking or show your work.

Remember, you need to buy at least 20 of gift 1. also remember, you have at most $1000 to spend.

How many of present 1?
How many of present 2?​

Answer 1

To solve this problem, we need to determine if it is a system of equations or inequalities. In part 1, we write the equations for the given prices of the presents. In part 2, we set up the system of inequalities based on the conditions. We then find a possible solution by plugging in values.

Step-by-step explanation:

In this scenario, we are given two presents with their respective prices, x and y variables, and certain conditions to satisfy. To determine whether this is a system of equations or inequalities, we need to consider the conditions given.

Part 1:

We have two presents: Present 1 costs $26.99 and Present 2 costs $35.99. We can write the equation as follows:

x = 26.99 and y = 35.99

Part 2:

We are required to buy at least 20 items of Present 1 and have a budget limit of $1000. We can write the system of inequalities as:

x ≥ 20 and 26.99x + 35.99y ≤ 1000

To find a possible solution where we buy at least one present for each employee, we need to consider the total number of employees (60) and the constraint of buying at least 20 items of Present 1. Let's assume we buy 20 items of Present 1 and distribute the remaining budget among Present 2:

x = 20, y = (1000 - 26.99x) / 35.99

Plugging in the values, we can find the number of Present 2:

x = 20, y ≈ 13.89

Therefore, one possible solution is to buy 20 items of Present 1 and approximately 14 items of Present 2.