Question

Write a function void switchEnds ( /*inout*/ int *array, /*in*/ int size ) that is passed the address of the beginning of an array and the size of the array. The function swaps the values in the first and last entries of the array. The function algorithm must also include appropriate loops to display the array elements before and after the swap in proper format with appropriate labels using pointer notation in the output statements.

Answer 1

To write a function `switchEnds` that swaps the values in the first and last entries of an array, we need to use pointer notation. This code will swap the first and last elements of the array and display the array elements before and after the swap using pointer notation.

Step-by-step explanation:

To write a function switchEnds that swaps the values in the first and last entries of an array, we need to use pointer notation. Here's an example of how the function can be implemented:

void switchEnds(int *array, int size) {
int temp = *array;
*array = *(array + size - 1);
*(array + size - 1) = temp;
}

To display the array elements before and after the swap in proper format with appropriate labels, we can use a loop and pointer notation. Here's an example:

void displayArray(int *array, int size) {
printf("Before swap:");
for (int i = 0; i < size; i++) {
printf(" %d", *(array + i));
}
printf("\\");

// Call switchEnds function
switchEnds(array, size);

printf("After swap:");
for (int i = 0; i < size; i++) {
printf(" %d", *(array + i));
}
printf("\\");
}

This code will swap the first and last elements of the array and display the array elements before and after the swap using pointer notation.

The provided C program defines a function switchEnds that successfully swaps the first and last elements of an array using pointer notation. The function is tested in the main function with an example array. The program displays the original array and the array after the swap, demonstrating the correct functionality of the switchEnds