Question

Vvnat is tne output or the rollowing program? \#include using namespace std; int main() \{ int x=3,y=5 bool z= true; if ((y7)&&z) cout ≪ "yes" ≪< endl; else cout ≪ "no" ≪< endl; while (x<3) cout ≪< "yes" ≪< endl; return 0 ; \}

no
yes yes
yes
no yes

Answer 1

The provided C++ code has a syntax error in the condition, however assuming it meant to check if y > 7, the output would be "no" as the condition evaluates to false, and the while loop will not execute since it does not satisfy the condition x < 3.

Step-by-step explanation:

The provided C++ program is intended to output either "yes" or "no" based on the evaluation of a conditional statement and also perform a loop operation. However, there is a syntax error due to the missing operator in the condition ((y7)&&z). Assuming it should be ((y > 7) && z), the condition would evaluate to false because the variable y is 5 which is not greater than 7. Since z is true, the && (AND) operator would eventually yield false because one of the operands is false (y > 7). Therefore, the first part would output "no".

The while loop will not execute because x is initialized with 3, and the loop condition (x < 3) checks if x is less than 3, which is not the case. As a result, the loop's body will be skipped, and no further "yes" will be printed by the program.

Overall, the output of the program would simply be:

no