Question

G(x)= (x+2)/(x^2+2x-3)

Answer 1

G(x) is undefined when x=−3 and x=1 since these are the values that would make the denominator zero.

The function you've provided is
`g(x)= (x+2)/((x+3)(x-1))`

To work with this function, let's first factorize the denominator to simplify it.

The denominator, x^2 +2x−3, can be factorized as

(x+3)(x−1). Therefore, the function becomes:

G(x)=
`(x+2)/((x+3)(x-1))`

​This function is defined for all real numbers except where the denominator becomes zero (as division by zero is undefined). So,

G(x) is undefined when x=−3 and x=1 since these are the values that would make the denominator zero.